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if (x^2-yz)/(a^2-bc)=(y^2-zx)/(b^2-ca)=(z^2-xy)/(c^2-ab); then prove that x/a=y/b=z/c

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Title : if (x^2-yz)/(a^2-bc)=(y^2-zx)/(b^2-ca)=(z^2-xy)/(c^2-ab); then prove that x/a=y/b=z/c
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