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	In triangle ABC, angle BAC=90, AD is the bisector of angle BAC and DE is perpendicular to AC. Prove (Anita mathematic classes) View
	In Fig. 7.55, ∠BAC=90°, AD is its bisector. If DE⊥AC, prove that DE×(AB+AC)=AB×AC. (2Pi classes) View
	In the given figure, `angle BAC=90^(@) and AD bot BC`.then, (Doubtnut) View
	In the given figure, ∠BCA = 90° and AD ⊥ BC, then: (A4S Doubts Engine) View
	Prove that AC+AD=BC/ Solve step by step/ Geometry Question (The Maths - Tuber) View
	In ΔABC, D⊥BC , such that AD2 = BD×CD. Prove that ΔABC is right angled at (A4S Doubts Engine) View
	In ∆abc ad is perpendicular on bc and ad2 = bd.dc , prove that angle bac is a right angle \| class X (MA Yazdani) View
$Download Lagu In $ \triangle \mathrm{ABC}, \angle \mathrm{BAC}=90^{\circ}, \mathrm{AD} $ is its bisector. If...$	In $ \triangle \mathrm{ABC}, \angle \mathrm{BAC}=90^{\circ}, \mathrm{AD} $ is its bisector. If... (PW Solutions) View
	In triange ABC, Angle B is greater than Angle C. If AM is the Bisector of Angle BAC and AN is Per (Focus Classes - Maths 9 \u0026 10) View
	In the following figure ABC is a right angled triangle with angleBAC=90^(@),andADbotBC. If BD = ... (Doubtnut) View