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Problem 1.6 prove that [ Ax(BxC)]+[Bx(CxA)]+[Cx(AxB)]=0 under what conditions does Ax(BxC)=(AxB)xB

Title : Problem 1.6 prove that [ Ax(BxC)]+[Bx(CxA)]+[Cx(AxB)]=0 under what conditions does Ax(BxC)=(AxB)xB
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